6.  Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post.If the length of each train be 120 meters in what time (in seconds) will they cross each other traveling in opposite direction?


10
12
15
20


Answer

 Option

Speed of first train = (120/10) m/sec = 12 m/sec Speed of the 2'nd train =(120/15) m/sec = 8m/sec Relative speed = (12+8) = 20 m/sec Required time = (120+120)/20 sec = 12 seconds.

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7.  Two trains are running in opposite directions with the same speed.If the length of each train is 120 meters and they cross each other in 12 seconds then the speed of each train (in km/hr) is?


10
18
36
72


Answer

 Option

Let the speed of each train be X m/sec Relative speed of the two trains =2 x m/sec So 2x = (120+120)/12 = 2x = 20 X = 10 Speed of each train = 10m/sec = (10*18/5) km/hr = 36 km/hr

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8.  A 270 meters long train running at the speed of 120 km/ph crosses other train running in opposite direction at the speed of 80 km/ph in 9 seconds.What is the length of the other train?


230 m
240 m
260 m
320 m


Answer

 Option

Relative speed = (120+80) km/hr = (200*5/18)m/sec = (500/9) m/sec Let the length of the other train be x meters Then x+270/9 =500/9 = x+270 = 500 = x =230 m

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9.  Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr.The faster train passes the slower train in 36 seconds. The length of each train is?


50 m
72 m
80 m
82 m


Answer

 Option

Let the length of each of train be X meters, Then distance covered = 2x meters. Relative speed = (46-36) km /hr = ( 10*5/18) m/sec = (25/9) m/sec 2x/36= 25/9 = 2x =100 = x= 50

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10.  Two goods train each 500 m long are running in opposite directions on parallel tracks.Their speeds are 45 km/hr and 30 km/hr respectively.Find the time taken by the slower train to pass the driver of the faster one.


12 sec
24 sec
48 sec
60 sec


Answer

 Option

Relative speed =(45+30) km /hr =(75*5/18) m/sec =(125/6)m/sec Distance covered = (500+500) m = 1000m Required time =(1000*6/125) sec = 48 sec

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