1.  Train P overtakes train Q double its length and traveling at half of speed of train P in 36 seconds. Train P crosses train R going in the opposite direction at double its speed in 8 seconds. If the speed of train P is 72 km/ph then the length of train R is?


330 m
360 m
390 m
420 m


Answer

 Option

For Train P length = L, Speed = 72 kmph For train Q length = 2L, Speed = 36 kmph (L + 2L)/(72 - 36)X5/18 L= 120 meter For train R Speed = 2 X 72 = 144 kmph & length = x meter (120 + x) / (144 + 72)X5/18 = 8 x = 360 meter

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

2.  Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction.Fast train completely passes a man sitting in the slower train in 5 seconds.What is the length of the fast train?


23 m
23 2/9 m
27 m
27 7/9 m


Answer

 Option

Relative speed =( 40-20) km/hr = (20*5/18) m/sec = (50/9)m/sec Length of faster train = (50/9*5)m = 250/9 m = 27 7/9 m

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

3.  Two trains travel in opposite directions at 36 km/ph and 45 km/ph and a man sitting in slower train passes the faster train in 8 seconds.The length of the faster train is?


80 m
100 m
120 m
180 m


Answer

 Option

Relative speed =(36+45) km/hr =(81*5/18) m/sec = (45/2) m/sec Length of train =(45/2*8) m =180 m

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

4.  A train X speeding with 120 km/ph crosses another train Y running in the same direction,in 2 minutes.If the lengths of the trains X and Y be 100 m and 200 m respectively what is the speed of the train Y?


111 km/hr
123 km/hr
127 km/hr
129 km/hr


Answer

 Option

Let the speed of train Y be X km /hr Speed of X relative to Y = (120-x) km/hr =[(120-x)*5/18] m/sec = (600-5x/18) m/sec = 300/(600-5x/18) = 120 <=> 5400 = 120(600-5x) <=> x =111

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

5.  A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds.The speed of the second train is?


48 km/hr
54 km/hr
66 km/hr
82 km/hr


Answer

 Option

Let the speed of the 2'nd train be x km/hr Relative speed =(x+50)km/hr =[ (x+50)*5/18] m/sec = (250+5x/18) m/sec Distance covered =(108+112) = 220 m 220/(250+5x/18) = 6 <=> 250+5x = 660 <=> x = 82 km/hr

Workspace

Report
Mail id: Report Error:

Answer Workspace Report