1. Train P overtakes train Q double its length and traveling at half of speed of train P in 36 seconds. Train P crosses train R going in the opposite direction at double its speed in 8 seconds. If the speed of train P is 72 km/ph then the length of train R is?

A. 330 m B. 360 m C. 390 m D. 420 m

Answer Answer: Option B Explanation: For Train P
length = L, Speed = 72 kmph
For train Q
length = 2L, Speed = 36 kmph
(L + 2L)/(72 - 36)X5/18
L= 120 meter
For train R
Speed = 2 X 72 = 144 kmph
& length = x meter
(120 + x) / (144 + 72)X5/18 = 8
x = 360 meter

2. Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction.Fast train completely passes a man sitting in the slower train in 5 seconds.What is the length of the fast train?

A. 23 m B. 23 2/9 m C. 27 m D. 27 7/9 m

Answer Answer: Option D Explanation: Relative speed =( 40-20) km/hr = (20*5/18) m/sec = (50/9)m/sec
Length of faster train = (50/9*5)m = 250/9 m = 27 7/9 m

3. Two trains travel in opposite directions at 36 km/ph and 45 km/ph and a man sitting in slower train passes the faster train in 8 seconds.The length of the faster train is?

A. 80 m B. 100 m C. 120 m D. 180 m

Answer Answer: Option D Explanation: Relative speed =(36+45) km/hr =(81*5/18) m/sec = (45/2) m/sec
Length of train =(45/2*8) m =180 m

4. A train X speeding with 120 km/ph crosses another train Y running in the same direction,in 2 minutes.If the lengths of the trains X and Y be 100 m and 200 m respectively what is the speed of the train Y?

A. 111 km/hr B. 123 km/hr C. 127 km/hr D. 129 km/hr

Answer Answer: Option A Explanation: Let the speed of train Y be X km /hr
Speed of X relative to Y = (120-x) km/hr
=[(120-x)*5/18] m/sec = (600-5x/18) m/sec
= 300/(600-5x/18) = 120 <=> 5400 = 120(600-5x) <=> x =111

5. A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds.The speed of the second train is?

A. 48 km/hr B. 54 km/hr C. 66 km/hr D. 82 km/hr

Answer Answer: Option D Explanation: Let the speed of the 2'nd train be x km/hr
Relative speed =(x+50)km/hr =[ (x+50)*5/18] m/sec = (250+5x/18) m/sec
Distance covered =(108+112) = 220 m
220/(250+5x/18) = 6 <=> 250+5x = 660 <=> x = 82 km/hr