31.  Mr. kavin walks at 4/5 of his normal speed and takes 60 minutes more than the usual time. What will be the new time taken by Mr.kavin?

260 minutes
235 minutes
220 minutes
300 minutes

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Answer: Option  D Explanation:4/5 of speed = 5/4 of original time
5/4 of original time = original time + 60 minutes
1/4 of original time = 60 minutes
Thus, original time = 60*4 = 240 minutes = 240+60 = 300 minutes ```

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32.  A man takes twice as long to row a distance against the stream as to row the same distance in favor of the stream.The ratio of the speed of the boat ( in still water) and the stream is

2:1
3:1
3:2
4:3

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Answer: Option  B Explanation:Let man's rate upstream be X km/ph.Then his rate downstream = 2x km/ph
Speed in still water : Speed of stream = (2x + x /2): 2x-x/2) = 3x/2:x/2 = 3:1 ```

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33.  A boat running upstream takes 8 hours 48 minutes to cover a certain distance while it takes 4 hours to cover the same distance running downstream.What is the ratio between the speed of the boat and speed of the water current respectively?

2:1
3:2
8:3
Cannot be determined

```Answer

Answer: Option  C Explanation:Let the man's rate upstream be x km/ph and that downstream be y km/ph.Then distance covered upstream in 8 hrs 48 mins= Distance covered downstream in 4 hours => (x*8 4/5) = (y*4) => 44/5x = 4y => y=11/5 x
Required ratio = (y+x/2): (y-x/2) = (16x/5*1/2): (6x/5*1/2) = 8/5:3/5 = 8:3 ```

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34.  In 1 hour a boat goes 11 km along the stream and 5 km against the stream.The speed of the boat in still water (in km/hr) is?

3
5
8
9

```Answer

Answer: Option  C Explanation:Speed in still water = 1/2 (11+5) km/ph = 8km/ph ```

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35.  A man can row 9 1/3 km/hr in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. the speed of the current is/

3 1/3 km/hr
3 1/9 km/hr
4 2/3 km/hr
4 1/2 km/hr

```Answer

Answer: Option  C Explanation:Let speed upstream be x km/hr.then, speed downstream = 3x km/hr.
speed in still water = 1/2 (3x+x) km/hr = 2x km/hr.
Therefore 2x =28/3 => x= 14/3.
so, speed upstream = 14/3 km/hr ; speed downstream =14 km/hr
Hence, speed of the current = 1/2 (14- 14/3) km/hr = 14/3 km/hr =4 2/3 km/hr. ```

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