Answer Answer: Option A Explanation:Interest on Rs 240 in 2 yrs = 259.2 – 240 = 19.2 So interest on Rs 320 = 19.2*(320/240)*(4/2) = 51.2 So amount = 320+51.2
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Answer Answer: Option D Explanation:Explanation:-Let x, y and z be the amounts invested in schemes A, B and C respectively. Then, add individual interest to get total using Si= pxrxt/100 [x x 10 x 1]/100 + [y x 12 x 1]/100 + [z x 15 x 1]/100 = 3200 10x + 12y + 15z = 320000…. (i)Now, z = 240% of y =(12/5)y……… (ii)And, z = 150% of x =(3/2)x so,x=(2/3 )z = (2/3) x value of z from ii x= (2/3) x (12/5) y = (8/5)y………..(iii) From (i), (ii) and (iii), we have : 16y + 12y + 36y = 320000 64y = 320000 y = 5000 Sum invested in Scheme B = Rs. 5000
Answer Answer: Option C Explanation:Trick: (n+1) * x i.e. (3+1) *2500 N= No. of times it become X= SI
Answer Answer: Option C Explanation:T.D. = (B.G*100/R*T) = Rs.(270*100/12*3) = Rs.750 Therefore B.D.=Rs.(750+270) = Rs.1020
Answer Answer: Option B Explanation:P.W. = Rs.(540 - 90) = Rs.450. Therefore S.I. on Rs.450 =Rs.90 S.I. on Rs.540 = Rs.(90/450*540) = Rs.108 Therefore B.D. Rs.108