36.  David invested certain amount in three different schemes A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme C was 150% of the amount invested in Scheme A and 240% of the amount invested in Scheme B, what was the amount invested in Scheme B?


Rs 10000
Rs 8000
Rs 6500
Rs 5000


Answer

 Option

Explanation:-Let x, y and z be the amounts invested in schemes A, B and C respectively. Then, add individual interest to get total using Si= pxrxt/100 [x x 10 x 1]/100 + [y x 12 x 1]/100 + [z x 15 x 1]/100 = 3200 10x + 12y + 15z = 320000…. (i)Now, z = 240% of y =(12/5)y……… (ii)And, z = 150% of x =(3/2)x so,x=(2/3 )z = (2/3) x value of z from ii x= (2/3) x (12/5) y = (8/5)y………..(iii) From (i), (ii) and (iii), we have : 16y + 12y + 36y = 320000 64y = 320000 y = 5000 Sum invested in Scheme B = Rs. 5000

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37.  A portion of $6600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from the portion earning a 5% return is twice that of the other portion, what is the total income from the two investments after one year?


200
270
250
.270


Answer

 Option

Explanation – 5x + 3y = z (total) x + y = 6600 5x= 2(3y) [ condition given] 5x – 6y = 0 x + y = 6600 5x -6y = 0 Subtract both equations and you get x = 3600 so y = 3000 3600*.05 = 180 3000*.03 = 90 z (total) = 270

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38.  A certain sum is invested for T years. It amounts to Rs. 400 at 10% per annum. But when invested at 4% per annum, it amounts to Rs. 200. Find the time (T)?


50years
41 years
41years
39 years


Answer

 Option

Explanation – We have, A1 = Rs. 400, A2 = Rs. 200, R1 = 10%, R2 = 4% Time (T) = [A1 – A2] x 100 divide by A2R1 – A1R2 = [400 – 200]x 100 divide by [200 x 10 – 400 x 4]= 20000/400 = 50 Years.

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39.  An automobile financier claims to be lending money at the simple interest, but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes?


10.80%
10.10%
10.25%%
10%


Answer

 Option

Explanation – Let the sum be Rs. 100. Then, S.I. for first 6 months = Rs. [100 x 10 x 1] / [100×2]= Rs. 5. S.I. for last 6 months = Rs.[105 x 10 x 1] / [100 x 2]= Rs. 5.25 So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs. 110.25. Effective rate = (110.25 – 100) = 10.25%.

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40.  Ravi lent out Rs.9600 at 8.5% per annum for a year 2 years 6 months.At the end of the duration,what amount he earned?


1200
4020
2040
2000


Answer

 Option

Explanation : R =2 +6/12 = 5/2 PNR/100 = 9600*85*5/100*10*2 = 4080000/2000 = 2040

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