Answer Answer: Option D Explanation:Explanation:-Let x, y and z be the amounts invested in schemes A, B and C respectively. Then, add individual interest to get total using Si= pxrxt/100 [x x 10 x 1]/100 + [y x 12 x 1]/100 + [z x 15 x 1]/100 = 3200 10x + 12y + 15z = 320000…. (i)Now, z = 240% of y =(12/5)y……… (ii)And, z = 150% of x =(3/2)x so,x=(2/3 )z = (2/3) x value of z from ii x= (2/3) x (12/5) y = (8/5)y………..(iii) From (i), (ii) and (iii), we have : 16y + 12y + 36y = 320000 64y = 320000 y = 5000 Sum invested in Scheme B = Rs. 5000
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Answer Answer: Option B Explanation:Explanation – 5x + 3y = z (total) x + y = 6600 5x= 2(3y) [ condition given] 5x – 6y = 0 x + y = 6600 5x -6y = 0 Subtract both equations and you get x = 3600 so y = 3000 3600*.05 = 180 3000*.03 = 90 z (total) = 270
Answer Answer: Option A Explanation:Explanation – We have, A1 = Rs. 400, A2 = Rs. 200, R1 = 10%, R2 = 4% Time (T) = [A1 – A2] x 100 divide by A2R1 – A1R2 = [400 – 200]x 100 divide by [200 x 10 – 400 x 4]= 20000/400 = 50 Years.
Answer Answer: Option C Explanation:Explanation – Let the sum be Rs. 100. Then, S.I. for first 6 months = Rs. [100 x 10 x 1] / [100×2]= Rs. 5. S.I. for last 6 months = Rs.[105 x 10 x 1] / [100 x 2]= Rs. 5.25 So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs. 110.25. Effective rate = (110.25 – 100) = 10.25%.
Answer Answer: Option C Explanation:Explanation : R =2 +6/12 = 5/2 PNR/100 = 9600*85*5/100*10*2 = 4080000/2000 = 2040