1.  A sum of money becomes 8 times at SI rate of 5% p.a. At what rate percent will it become twelve fold?

None of these
7(6/7)%
5(6/7)%
6(6/7)%

```Answer

Answer: Option  B Explanation:[ (m-1) *r ] / n-1
[(12-1) *5] /(8-1) ```

Report

2.  Sankar borrowed some money at the rate of 4% pa for the first 4 years,6% for the next 3 years and 7% for the next 10 years.If the total interest paid by him is Rs.8528,how much money did he borrow?

None of these
16728
8328
8200

```Answer

Answer: Option  D Explanation:x*4*4/100 + x*6*3/100 + x*7*10/100 =8523
16x + 17x + 70x/100 = 8528
104 x = 852800
x = 852800/104 = 8200
```

3.  A sum was put at a certain rate of interest for four years. Had it been put at a rate of interest 4% higher than the previous rate of interest, it would have fetched Rs. 80 more. What is the sum?

475
700
450
500

```Answer

Answer: Option  D Explanation:x*4*(r+4)/100 – (x*4*r)/100 = 80
4xr+16x – 4xr = 8000
X = 8000/16 =500 ```

Report

4.  Rs. 12000 was invested for 2 years, partly in scheme A at the rate of 5% SI per annum and partly in scheme B at the rate of 8% SI per annum. The total interest received at the end was Rs.1800. What amount of money was invested in scheme A?

1600
2000
4200
3200

```Answer

Answer: Option  B Explanation:x *5*2/100 + (12000-x)*2*8/100 = 1800
x/10 + 192000-16x/100 = 1800
10x+192000-16x=180000
6x = 12,000
X=2000 ```

Report

5.  If the annual rate of simple interest increases from 10% to 12(1/2)%,annual income increases by 2500 then the principal(Rs)?

1,02,500
1,25,000
)10,000
1,00,000

```Answer

Answer: Option  D Explanation:x *25*1/2*100 - x*10*1/100 = 2500
= 25x - 20x/200 = 2500
= 5x = 500000
= x = 500000/5 = 1,00,000 ```

Report