1.  Two trains travel in opposite directions at 36 km/ph and 45 km/ph and a man sitting in slower train passes the faster train in 8 seconds.The length of the faster train is?


80 m
100 m
120 m
180 m


Answer

 Option

Relative speed =(36+45) km/hr =(81*5/18) m/sec = (45/2) m/sec Length of train =(45/2*8) m =180 m

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2.  Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post.If the length of each train be 120 meters in what time (in seconds) will they cross each other traveling in opposite direction?


10
12
15
20


Answer

 Option

Speed of first train = (120/10) m/sec = 12 m/sec Speed of the 2'nd train =(120/15) m/sec = 8m/sec Relative speed = (12+8) = 20 m/sec Required time = (120+120)/20 sec = 12 seconds.

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3.  Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr.The faster train passes the slower train in 36 seconds. The length of each train is?


50 m
72 m
80 m
82 m


Answer

 Option

Let the length of each of train be X meters, Then distance covered = 2x meters. Relative speed = (46-36) km /hr = ( 10*5/18) m/sec = (25/9) m/sec 2x/36= 25/9 = 2x =100 = x= 50

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4.  Two trains are running in opposite directions with the same speed.If the length of each train is 120 meters and they cross each other in 12 seconds then the speed of each train (in km/hr) is?


10
18
36
72


Answer

 Option

Let the speed of each train be X m/sec Relative speed of the two trains =2 x m/sec So 2x = (120+120)/12 = 2x = 20 X = 10 Speed of each train = 10m/sec = (10*18/5) km/hr = 36 km/hr

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5.  Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction.Fast train completely passes a man sitting in the slower train in 5 seconds.What is the length of the fast train?


23 m
23 2/9 m
27 m
27 7/9 m


Answer

 Option

Relative speed =( 40-20) km/hr = (20*5/18) m/sec = (50/9)m/sec Length of faster train = (50/9*5)m = 250/9 m = 27 7/9 m

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