1.  What is the probability of getting a sum 9 from two throws of a dice?


1/6
1/8
1/9
1/12


Answer

 Option

In two throws of a dice, n(S) = 6*6 =36. Let E = event of getting a sum 9 = {(3,6),(4,5),(5,4),(6,3)} Therefore P(E) = n(E)/n(S) = 4/36 = 1/9

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

2.  Two dice are tossed. The probability that they total score is a prime number is?


1/6
5/12
1/2
7/9


Answer

 Option

Clearly, n(S) = (6*6) = 36 Let E = Event that the sum is a prime number Then, E = {(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)} Therefore n(E) = 15 Therefore P(E) = n(E)/n(S) = 15/36 = 5/12.

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

3.  Two dice are thrown together. What is the probability that the sum of the numbers on the two faces is divisible by 4 or 6?


2/18
5/18
4/18
7/18


Answer

 Option

Clearly, n(S) = 6*6 =36. Let E be the event that the sum of the numbers on the two faces is divisible by 4 or 6. Then E = {(1,3), (1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6) Therefore n(E) = 14 Hence P(E) = n(E)/n(S) = 14/36 = 7/18

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

4.  Two dice are thrown simultaneously. What is the probability of getting 2 numbers whose product is even?


3/4
4/3
1/4
1/3


Answer

 Option

3/4

Workspace

Report
Mail id: Report Error:

Answer Workspace Report

5.  Two dice are thrown simultaneously. What is the probability of getting 2 numbers whose product is even?


3/4
4/3
1/4
1/3


Answer

 Option

Answer : 3/4

Workspace

Report
Mail id: Report Error:

Answer Workspace Report