1.  A container filled with liquid containing 4 parts of water and 6 parts of milk. How much of mixture must be drawn off and filled with water so that the mixture contains half milk and half water.


1/4
1/3
1/6
1/5


Answer

 Option

Let water = 40ltr and milk is 60ltr. Water = 40 – x*(2/5) + x and milk = 60 – x*(3/5) [x is the amount of mixture taken out] Equate both the equation, we get x = 50/3. Now, mixture drawn off = (50/3)/100 = 1/6

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2.  A painter mixes blue paint with white paint so that the mixture contains 10% blue paint.In a mixture of 40 litres paint how many litres blue paint should be added so that the mixture contains 20% of blue paint?


2.5 litres
4litres
5litres
2 litres


Answer

 Option

Percentage of blue point, in pure Blue point =100% So, 8 : 1 Since 8 = 40 1 = 5 liters

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3.  Two cans P and Q contains milk and water in the ratio of 3:2 and 7:3 respectively. The ratio in which these two cans be mixed so as to get a new mixture containing milk and water in the ratio 7:4.


4:7
7:3
7:4
7:5


Answer

 Option

Milk in 1st can = 3/5 and water = 2/5. Similarly in second can milk = 7/10 and water = 3/10. Take the ratio = K:1 (3k/5 + 7/10)/(2k/5 + 3/10) = 7/4 Solve for k, we get k = 7/4. So the ratio is 7:4

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4.  Two bottles A and B contain diluted sulphuric acid. In a bottle A, the amount of water is double the amount of acid while in bottle B, The amount of acid is 3 times that of water. How much mixture should be taken from each bottle in order to prepare 5 litres diluted sulphuric acid containing equal amount of acid and water?


1,4
4,1
3,2
2,3


Answer

 Option

In a bottle a ratio acid : water = 1:2, B = 3:1 Mixture 1:1, required acid = 1/2 1/3 3/4 ............1/2............. 1/4 1/6

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5.  A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?


1/3
1/4
1/5
1/7


Answer

 Option

suppose the vessel initially contains 8 litres of liquid. Let x litres of this liquid be replaced with water. Quantity of water in new mixture = (3 - 3x/8 +x) litres. Quantity of syrup in new mixture = (5 - 5x/8) litres Therefore (3 - 3x/8 + x) = (5 - 5x/8) => 5x +24 = 40 - 5x => 10x =16 => x = 8/5. So, part of the mixture replaced = (8/5*1/8) = 1/5.

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