1.  The area of a right-angled triangle is 40 times its base. What is its height ?


45 cm
60 cm
80 cm
Data inadequate


Answer

 Option

△ = 12 * Base * Height = 40 * Base = 12 * Base * Height Height = 80 cm.

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2.  ABC is a triangle with base AB, D is a point on AB such that AB = 5 and DB = 3. What is the ratio of the area of △ ADC to the area of △ ABC ?


2 : 3
3 : 2
2 : 5
3 : 5


Answer

 Option

a =5, b = 12 and c = 13, So, s = 12(5 + 12 + 13) cm = 15 cm. Area = 15 * 10 * 3 * 2 = 30 cm2. 12 * 12 * Height = 30. Height = 5 cm.

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3.  If every side of a triangle is doubled, the area of the new triangle is K times the area of the old one. K is equal to :


2
2
3
4


Answer

 Option

A1 = 32 a2 and A2 = 32(2a)2 = 4 * 32 a2 = 4A1. K = 4.

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4.  If the area of an equilateral triangle is 243 sq. cm, then its perimeter is :


26 cm
46 cm
126 cm
96 cm


Answer

 Option

Area of an equilateral triangle of side a cm = (34 a2) cm2. 34 a2 = 243. a2 = 96. a = 46. Perimeter = 3a = 126cm.

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5.  The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.


200 m
250 m
300 m
350 m


Answer

 Option

Area of the field = Total costRate = (333.1824.68) hectares = 13.5 hectares. = (13.5 * 10000) m2 = 135000 m2. Let altitude = x metres and base = 3x metres. Then, 12 * 3x * x = 135000. x2 = 90000. x = 300.

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