1.  What will be the cost of gardening 1 metre broad boundary around a rectangular plot having perimeter of 340 metres at the rate of Rs. 10 per square metre ?

Rs. 1700
Rs. 3400
Rs. 3440
Cannot be determined

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Answer: Option  C Explanation:2(l + b) = 340 (Given).
Area of the boundary = [(l + 2) (b + 2) - lb] = 2(l + b) + 4 = 344.
Cost of gardening = Rs. (344 * 10) = Rs. 3440. ```

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2.  A square and a rectangle have equal areas. If their perimeters are p1 and p2 respectively, then :

p1 < p2
p1 = p2
p1 > p2
None of the above

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Answer: Option  A Explanation:A square and a rectangle with equal areas will satisfy the relation p1 < p2. ```

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3.  If the ratio of areas of two squares is 225 : 256, then the ratio of their perimeters is :

225 : 256
256 : 225
15 : 16
16 : 15

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Answer: Option  C Explanation:a2⁄b2 = 225⁄256 = (15)2⁄(16)2.
a⁄b = 15⁄16.
4a⁄4b = 4 * 15⁄4 * 16 = 15⁄16.
Ratio of perimeters = 15 : 16.
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4.  What will be the length of the diagonal of that square plot where area is equal to the area of a rectangular plot of length 45 metres and breadth 40 metres ?

42.5 metres
60 metres
75 metres

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Answer: Option  B Explanation:Area = (45 * 40) m$\sqrt{2}$ = 1⁄2 * (diagonal)2 = 1800.
diagonal = 60 m. ```

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5.  of the two square fields, the area of one is 1 hectare while the other one is broader by 1%. The difference in their areas is :

100 m2
101 m2
200 m2
201 m2

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Answer: Option  D Explanation:Area = 1 hect = 10000sq. m = side = $\sqrt{\mathrm{10000}}$ m = 100 m.
side of the other squae = 101 m.
Difference in their areas = [(101)2 - (100)2] m2.
= [(101 + 100) (101 - 100)] m2 = 201 m2. ```

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