1.  What will be the cost of gardening 1 metre broad boundary around a rectangular plot having perimeter of 340 metres at the rate of Rs. 10 per square metre ?


Rs. 1700
Rs. 3400
Rs. 3440
Cannot be determined


Answer

 Option

2(l + b) = 340 (Given). Area of the boundary = [(l + 2) (b + 2) - lb] = 2(l + b) + 4 = 344. Cost of gardening = Rs. (344 * 10) = Rs. 3440.

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2.  A square and a rectangle have equal areas. If their perimeters are p1 and p2 respectively, then :


p1 < p2
p1 = p2
p1 > p2
None of the above


Answer

 Option

A square and a rectangle with equal areas will satisfy the relation p1 < p2.

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3.  If the ratio of areas of two squares is 225 : 256, then the ratio of their perimeters is :


225 : 256
256 : 225
15 : 16
16 : 15


Answer

 Option

a2b2 = 225256 = (15)2(16)2. ab = 1516. 4a4b = 4 * 154 * 16 = 1516. Ratio of perimeters = 15 : 16.

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4.  What will be the length of the diagonal of that square plot where area is equal to the area of a rectangular plot of length 45 metres and breadth 40 metres ?


42.5 metres
60 metres
75 metres
Data inadequate


Answer

 Option

Area = (45 * 40) m2 = 12 * (diagonal)2 = 1800. diagonal = 60 m.

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5.  of the two square fields, the area of one is 1 hectare while the other one is broader by 1%. The difference in their areas is :


100 m2
101 m2
200 m2
201 m2


Answer

 Option

Area = 1 hect = 10000sq. m = side = 10000 m = 100 m. side of the other squae = 101 m. Difference in their areas = [(101)2 - (100)2] m2. = [(101 + 100) (101 - 100)] m2 = 201 m2.

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